54 lines
		
	
	
		
			1.5 KiB
		
	
	
	
		
			Python
		
	
	
		
			Executable File
		
	
	
	
	
			
		
		
	
	
			54 lines
		
	
	
		
			1.5 KiB
		
	
	
	
		
			Python
		
	
	
		
			Executable File
		
	
	
	
	
| #!/usr/bin/python3
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| # Licensed under the Apache License, Version 2.0 (the "License");
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| # you may not use this file except in compliance with the License.
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| # You may obtain a copy of the License at
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| #
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| #    http://www.apache.org/licenses/LICENSE-2.0
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| #
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| # Unless required by applicable law or agreed to in writing, software
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| # distributed under the License is distributed on an "AS IS" BASIS,
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| # WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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| # See the License for the specific language governing permissions and
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| # limitations under the License.
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| """ KCPassword Xor """
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| 
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| # MSc Project in Royal Holloway, University of London.
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| __author__ = 'Joaquin Moreno Garijo (bastionado@gmail.com)'
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| 
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| import sys
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| 
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| magic_static='7d895223d2bcddeaa3b91f'
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| pwd = ''
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| 
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| if len(sys.argv) != 2:
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|   print( 'Please write as a first argv the hexadecimal kcpassword value:' )
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|   print( 'Example: python {} 1ceb3147d2172f1140ff63bf'.format(sys.argv[0]) )
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|   exit(1)
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| 
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| kcpasswd=sys.argv[1]
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| print( '\n\tKcpasswd: 0x{}.'.format(kcpasswd) )
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| print( '\tMagic Xor: 0x{}.'.format(magic_static) )
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| 
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| tam_xor = len(magic_static)
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| tam = len(kcpasswd) - tam_xor
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| magic = magic_static
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| while tam > 0:
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|   tam -= tam_xor
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|   magic += magic_static
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| print( '\tUsed Magic Xor: 0x{}.'.format(magic) )
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| 
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| i = 0
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| while i < len(kcpasswd):
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|   charkc = kcpasswd[i] + kcpasswd[i+1]
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|   charkch = int(charkc, 16)
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|   charm = magic[i] + magic[i+1]
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|   charmh = int(charm, 16)
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|   r = charkch ^ charmh
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|   pwd += chr(r)
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|   if r == 0:
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|     print( '\n\tThe password is: "{}".\n'.format(pwd.rstrip('\0')) )
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|     break
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|   i += 2
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| 
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| exit(0)
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